Fix scrape interval length calculation

pull/1404/head
Fabian Reinartz 9 years ago
parent 1a3253e8ed
commit fbe251c2df

@ -235,9 +235,12 @@ func (sl *scrapeLoop) run(interval, timeout time.Duration, errc chan<- error) {
scrapeCtx, _ = context.WithTimeout(sl.ctx, timeout)
)
targetIntervalLength.WithLabelValues(interval.String()).Observe(
float64(time.Since(last)) / float64(time.Second), // Sub-second precision.
)
// Only record after the first scrape.
if !last.IsZero() {
targetIntervalLength.WithLabelValues(interval.String()).Observe(
float64(time.Since(last)) / float64(time.Second), // Sub-second precision.
)
}
samples, err := sl.scraper.scrape(scrapeCtx, start)
if err == nil {

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