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When the exemplar type is an int, it incorrectly gets converted to a 0 when DoubleValue() is called on the exemplar. This adds a check to ensure that the value is converted properly based on the type. Signed-off-by: Charlie Le <charlie_le@apple.com>pull/15217/head
Charlie Le
4 weeks ago
2 changed files with 44 additions and 1 deletions
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