0 400 400   %% Correctly defined arguments block
 2 400 401 + function y = foo (x)
 0 401 401 | % Some comment here
 0 401 401 | % And, maybe, here
 1 401 401 | 
 2 401 402 + arguments
 0 402 402 |     x (1,2) {mustBeReal(x)}
 0 402 401 | end
 1 401 401 | 
 0 401 401 | y = x*2;
 0 401 401 | arguments = 1;
 0 401 401 | y = y + arguments;
 0 401 400 | end
 1 400 400   
 0 400 400   %% No arguments block, "arguments" is used 
 0 400 400   %  as a variable name (identifier)
 0 400 400   % Prevent arguments from folding with an identifier
 2 400 401 + function y = foo (x)
 0 401 401 | % Some comment here
 0 401 401 | x = x + 1;
 0 401 401 | arguments = 10;
 0 401 401 | y = x + arguments;
 0 401 400 | end
 1 400 400   
 0 400 400   % Prevent arguments from folding with a number
 2 400 401 + function y = foo (x)
 0 401 401 | 4
 0 401 401 | arguments = 10;
 0 401 401 | y = x + arguments;
 0 401 400 | end
 1 400 400   
 0 400 400   % With a double quote string
 2 400 401 + function y = foo (x)
 0 401 401 | "test"
 0 401 401 | arguments = 10;
 0 401 401 | y = x + arguments;
 0 401 400 | end
 1 400 400   
 0 400 400   % With a string
 2 400 401 + function y = foo (x)
 0 401 401 | 'test'
 0 401 401 | arguments = 10;
 0 401 401 | y = x + arguments;
 0 401 400 | end
 1 400 400   
 0 400 400   % With a keyword
 2 400 401 + function y = foo (x)
 2 401 402 + if x == 0;
 0 402 402 |     return 0;
 0 402 401 | end
 0 401 401 | arguments = 10;
 0 401 401 | y = x + arguments;
 0 401 400 | end
 1 400 400   
 0 400 400   % With an operator (illegal syntax)
 2 400 401 + function y = foo (x)
 0 401 401 | *
 0 401 401 | arguments = 10;
 0 401 401 | y = x + arguments;
 0 401 400 | end
 1 400 400   
 0 400 400   % Arguments block is illegal in nested functions,
 0 400 400   % but lexer should process it anyway
 2 400 401 + function y = foo (x)
 2 401 402 + arguments
 0 402 402 |     x (1,2) {mustBeReal(x)}
 0 402 401 | end
 1 401 401 | 
 2 401 402 +     function y = foo (x)
 2 402 403 +     arguments
 0 403 403 |         x (1,2) {mustBeReal(x)}
 0 403 402 |     end
 0 402 402 |     arguments = 5;
 0 402 402 |     y = arguments + x;
 0 402 401 |     end
 1 401 401 | 
 0 401 401 | % Use as a variable, just in case
 0 401 401 | arguments = 10;
 0 401 400 | end
 1 400 400   
 0 400 400   % Erroneous use of arguments block
 2 400 401 + function y = foo(x)
 0 401 401 | % Some comment
 0 401 401 | x = x + 1;
 0 401 401 | arguments
 0 401 401 |     x
 0 401 400 | end
 0 400 400   y = x;
 0 400 3ff   end