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修复 `layer.min(index)` 方法与最小化按钮事件效果不一致的问题

pull/1253/head
贤心 2 years ago
parent
commit
aca0231473
  1. 6
      src/modules/layer.js

6
src/modules/layer.js

@ -1025,8 +1025,6 @@ layer.style = function(index, options, limit){
// 最小化
layer.min = function(index, options){
options = options || {};
var layero = $('#'+ doms[0] + index);
var maxminStatus = layero.data('maxminStatus');
@ -1034,8 +1032,10 @@ layer.min = function(index, options){
if(maxminStatus === 'max') layer.restore(index); // 若当前为最大化,则先还原后再最小化
layero.data('maxminStatus', 'min');
options = options || layero.data('config') || {};
var shadeo = $('#'+ doms.SHADE + index);
var elemMin = layero.find('.layui-layer-min');
var titHeight = layero.find(doms[1]).outerHeight() || 0;
var minLeft = layero.attr('minLeft'); // 最小化时的横坐标
var hasMinLeft = typeof minLeft === 'string'; // 是否已经赋值过最小化坐标
@ -1077,7 +1077,7 @@ layer.min = function(index, options){
layero.attr('position', position);
layer.style(index, settings, true);
layero.find('.layui-layer-min').hide();
elemMin.hide();
layero.attr('type') === 'page' && layero.find(doms[4]).hide();
ready.rescollbar(index);

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