k3s/vendor/github.com/tchap/go-patricia/patricia/patricia.go

607 lines
15 KiB
Go

// Copyright (c) 2014 The go-patricia AUTHORS
//
// Use of this source code is governed by The MIT License
// that can be found in the LICENSE file.
package patricia
import (
"bytes"
"errors"
"fmt"
"io"
"strings"
)
//------------------------------------------------------------------------------
// Trie
//------------------------------------------------------------------------------
const (
DefaultMaxPrefixPerNode = 10
DefaultMaxChildrenPerSparseNode = 8
)
type (
Prefix []byte
Item interface{}
VisitorFunc func(prefix Prefix, item Item) error
)
// Trie is a generic patricia trie that allows fast retrieval of items by prefix.
// and other funky stuff.
//
// Trie is not thread-safe.
type Trie struct {
prefix Prefix
item Item
maxPrefixPerNode int
maxChildrenPerSparseNode int
children childList
}
// Public API ------------------------------------------------------------------
type Option func(*Trie)
// Trie constructor.
func NewTrie(options ...Option) *Trie {
trie := &Trie{}
for _, opt := range options {
opt(trie)
}
if trie.maxPrefixPerNode <= 0 {
trie.maxPrefixPerNode = DefaultMaxPrefixPerNode
}
if trie.maxChildrenPerSparseNode <= 0 {
trie.maxChildrenPerSparseNode = DefaultMaxChildrenPerSparseNode
}
trie.children = newSparseChildList(trie.maxChildrenPerSparseNode)
return trie
}
func MaxPrefixPerNode(value int) Option {
return func(trie *Trie) {
trie.maxPrefixPerNode = value
}
}
func MaxChildrenPerSparseNode(value int) Option {
return func(trie *Trie) {
trie.maxChildrenPerSparseNode = value
}
}
// Clone makes a copy of an existing trie.
// Items stored in both tries become shared, obviously.
func (trie *Trie) Clone() *Trie {
return &Trie{
prefix: append(Prefix(nil), trie.prefix...),
item: trie.item,
maxPrefixPerNode: trie.maxPrefixPerNode,
maxChildrenPerSparseNode: trie.maxChildrenPerSparseNode,
children: trie.children.clone(),
}
}
// Item returns the item stored in the root of this trie.
func (trie *Trie) Item() Item {
return trie.item
}
// Insert inserts a new item into the trie using the given prefix. Insert does
// not replace existing items. It returns false if an item was already in place.
func (trie *Trie) Insert(key Prefix, item Item) (inserted bool) {
return trie.put(key, item, false)
}
// Set works much like Insert, but it always sets the item, possibly replacing
// the item previously inserted.
func (trie *Trie) Set(key Prefix, item Item) {
trie.put(key, item, true)
}
// Get returns the item located at key.
//
// This method is a bit dangerous, because Get can as well end up in an internal
// node that is not really representing any user-defined value. So when nil is
// a valid value being used, it is not possible to tell if the value was inserted
// into the tree by the user or not. A possible workaround for this is not to use
// nil interface as a valid value, even using zero value of any type is enough
// to prevent this bad behaviour.
func (trie *Trie) Get(key Prefix) (item Item) {
_, node, found, leftover := trie.findSubtree(key)
if !found || len(leftover) != 0 {
return nil
}
return node.item
}
// Match returns what Get(prefix) != nil would return. The same warning as for
// Get applies here as well.
func (trie *Trie) Match(prefix Prefix) (matchedExactly bool) {
return trie.Get(prefix) != nil
}
// MatchSubtree returns true when there is a subtree representing extensions
// to key, that is if there are any keys in the tree which have key as prefix.
func (trie *Trie) MatchSubtree(key Prefix) (matched bool) {
_, _, matched, _ = trie.findSubtree(key)
return
}
// Visit calls visitor on every node containing a non-nil item
// in alphabetical order.
//
// If an error is returned from visitor, the function stops visiting the tree
// and returns that error, unless it is a special error - SkipSubtree. In that
// case Visit skips the subtree represented by the current node and continues
// elsewhere.
func (trie *Trie) Visit(visitor VisitorFunc) error {
return trie.walk(nil, visitor)
}
func (trie *Trie) size() int {
n := 0
trie.walk(nil, func(prefix Prefix, item Item) error {
n++
return nil
})
return n
}
func (trie *Trie) total() int {
return 1 + trie.children.total()
}
// VisitSubtree works much like Visit, but it only visits nodes matching prefix.
func (trie *Trie) VisitSubtree(prefix Prefix, visitor VisitorFunc) error {
// Nil prefix not allowed.
if prefix == nil {
panic(ErrNilPrefix)
}
// Empty trie must be handled explicitly.
if trie.prefix == nil {
return nil
}
// Locate the relevant subtree.
_, root, found, leftover := trie.findSubtree(prefix)
if !found {
return nil
}
prefix = append(prefix, leftover...)
// Visit it.
return root.walk(prefix, visitor)
}
// VisitPrefixes visits only nodes that represent prefixes of key.
// To say the obvious, returning SkipSubtree from visitor makes no sense here.
func (trie *Trie) VisitPrefixes(key Prefix, visitor VisitorFunc) error {
// Nil key not allowed.
if key == nil {
panic(ErrNilPrefix)
}
// Empty trie must be handled explicitly.
if trie.prefix == nil {
return nil
}
// Walk the path matching key prefixes.
node := trie
prefix := key
offset := 0
for {
// Compute what part of prefix matches.
common := node.longestCommonPrefixLength(key)
key = key[common:]
offset += common
// Partial match means that there is no subtree matching prefix.
if common < len(node.prefix) {
return nil
}
// Call the visitor.
if item := node.item; item != nil {
if err := visitor(prefix[:offset], item); err != nil {
return err
}
}
if len(key) == 0 {
// This node represents key, we are finished.
return nil
}
// There is some key suffix left, move to the children.
child := node.children.next(key[0])
if child == nil {
// There is nowhere to continue, return.
return nil
}
node = child
}
}
// Delete deletes the item represented by the given prefix.
//
// True is returned if the matching node was found and deleted.
func (trie *Trie) Delete(key Prefix) (deleted bool) {
// Nil prefix not allowed.
if key == nil {
panic(ErrNilPrefix)
}
// Empty trie must be handled explicitly.
if trie.prefix == nil {
return false
}
// Find the relevant node.
path, found, _ := trie.findSubtreePath(key)
if !found {
return false
}
node := path[len(path)-1]
var parent *Trie
if len(path) != 1 {
parent = path[len(path)-2]
}
// If the item is already set to nil, there is nothing to do.
if node.item == nil {
return false
}
// Delete the item.
node.item = nil
// Initialise i before goto.
// Will be used later in a loop.
i := len(path) - 1
// In case there are some child nodes, we cannot drop the whole subtree.
// We can try to compact nodes, though.
if node.children.length() != 0 {
goto Compact
}
// In case we are at the root, just reset it and we are done.
if parent == nil {
node.reset()
return true
}
// We can drop a subtree.
// Find the first ancestor that has its value set or it has 2 or more child nodes.
// That will be the node where to drop the subtree at.
for ; i >= 0; i-- {
if current := path[i]; current.item != nil || current.children.length() >= 2 {
break
}
}
// Handle the case when there is no such node.
// In other words, we can reset the whole tree.
if i == -1 {
path[0].reset()
return true
}
// We can just remove the subtree here.
node = path[i]
if i == 0 {
parent = nil
} else {
parent = path[i-1]
}
// i+1 is always a valid index since i is never pointing to the last node.
// The loop above skips at least the last node since we are sure that the item
// is set to nil and it has no children, othewise we would be compacting instead.
node.children.remove(path[i+1].prefix[0])
Compact:
// The node is set to the first non-empty ancestor,
// so try to compact since that might be possible now.
if compacted := node.compact(); compacted != node {
if parent == nil {
*node = *compacted
} else {
parent.children.replace(node.prefix[0], compacted)
*parent = *parent.compact()
}
}
return true
}
// DeleteSubtree finds the subtree exactly matching prefix and deletes it.
//
// True is returned if the subtree was found and deleted.
func (trie *Trie) DeleteSubtree(prefix Prefix) (deleted bool) {
// Nil prefix not allowed.
if prefix == nil {
panic(ErrNilPrefix)
}
// Empty trie must be handled explicitly.
if trie.prefix == nil {
return false
}
// Locate the relevant subtree.
parent, root, found, _ := trie.findSubtree(prefix)
if !found {
return false
}
// If we are in the root of the trie, reset the trie.
if parent == nil {
root.reset()
return true
}
// Otherwise remove the root node from its parent.
parent.children.remove(root.prefix[0])
return true
}
// Internal helper methods -----------------------------------------------------
func (trie *Trie) empty() bool {
return trie.item == nil && trie.children.length() == 0
}
func (trie *Trie) reset() {
trie.prefix = nil
trie.children = newSparseChildList(trie.maxPrefixPerNode)
}
func (trie *Trie) put(key Prefix, item Item, replace bool) (inserted bool) {
// Nil prefix not allowed.
if key == nil {
panic(ErrNilPrefix)
}
var (
common int
node *Trie = trie
child *Trie
)
if node.prefix == nil {
if len(key) <= trie.maxPrefixPerNode {
node.prefix = key
goto InsertItem
}
node.prefix = key[:trie.maxPrefixPerNode]
key = key[trie.maxPrefixPerNode:]
goto AppendChild
}
for {
// Compute the longest common prefix length.
common = node.longestCommonPrefixLength(key)
key = key[common:]
// Only a part matches, split.
if common < len(node.prefix) {
goto SplitPrefix
}
// common == len(node.prefix) since never (common > len(node.prefix))
// common == len(former key) <-> 0 == len(key)
// -> former key == node.prefix
if len(key) == 0 {
goto InsertItem
}
// Check children for matching prefix.
child = node.children.next(key[0])
if child == nil {
goto AppendChild
}
node = child
}
SplitPrefix:
// Split the prefix if necessary.
child = new(Trie)
*child = *node
*node = *NewTrie()
node.prefix = child.prefix[:common]
child.prefix = child.prefix[common:]
child = child.compact()
node.children = node.children.add(child)
AppendChild:
// Keep appending children until whole prefix is inserted.
// This loop starts with empty node.prefix that needs to be filled.
for len(key) != 0 {
child := NewTrie()
if len(key) <= trie.maxPrefixPerNode {
child.prefix = key
node.children = node.children.add(child)
node = child
goto InsertItem
} else {
child.prefix = key[:trie.maxPrefixPerNode]
key = key[trie.maxPrefixPerNode:]
node.children = node.children.add(child)
node = child
}
}
InsertItem:
// Try to insert the item if possible.
if replace || node.item == nil {
node.item = item
return true
}
return false
}
func (trie *Trie) compact() *Trie {
// Only a node with a single child can be compacted.
if trie.children.length() != 1 {
return trie
}
child := trie.children.head()
// If any item is set, we cannot compact since we want to retain
// the ability to do searching by key. This makes compaction less usable,
// but that simply cannot be avoided.
if trie.item != nil || child.item != nil {
return trie
}
// Make sure the combined prefixes fit into a single node.
if len(trie.prefix)+len(child.prefix) > trie.maxPrefixPerNode {
return trie
}
// Concatenate the prefixes, move the items.
child.prefix = append(trie.prefix, child.prefix...)
if trie.item != nil {
child.item = trie.item
}
return child
}
func (trie *Trie) findSubtree(prefix Prefix) (parent *Trie, root *Trie, found bool, leftover Prefix) {
// Find the subtree matching prefix.
root = trie
for {
// Compute what part of prefix matches.
common := root.longestCommonPrefixLength(prefix)
prefix = prefix[common:]
// We used up the whole prefix, subtree found.
if len(prefix) == 0 {
found = true
leftover = root.prefix[common:]
return
}
// Partial match means that there is no subtree matching prefix.
if common < len(root.prefix) {
leftover = root.prefix[common:]
return
}
// There is some prefix left, move to the children.
child := root.children.next(prefix[0])
if child == nil {
// There is nowhere to continue, there is no subtree matching prefix.
return
}
parent = root
root = child
}
}
func (trie *Trie) findSubtreePath(prefix Prefix) (path []*Trie, found bool, leftover Prefix) {
// Find the subtree matching prefix.
root := trie
var subtreePath []*Trie
for {
// Append the current root to the path.
subtreePath = append(subtreePath, root)
// Compute what part of prefix matches.
common := root.longestCommonPrefixLength(prefix)
prefix = prefix[common:]
// We used up the whole prefix, subtree found.
if len(prefix) == 0 {
path = subtreePath
found = true
leftover = root.prefix[common:]
return
}
// Partial match means that there is no subtree matching prefix.
if common < len(root.prefix) {
leftover = root.prefix[common:]
return
}
// There is some prefix left, move to the children.
child := root.children.next(prefix[0])
if child == nil {
// There is nowhere to continue, there is no subtree matching prefix.
return
}
root = child
}
}
func (trie *Trie) walk(actualRootPrefix Prefix, visitor VisitorFunc) error {
var prefix Prefix
// Allocate a bit more space for prefix at the beginning.
if actualRootPrefix == nil {
prefix = make(Prefix, 32+len(trie.prefix))
copy(prefix, trie.prefix)
prefix = prefix[:len(trie.prefix)]
} else {
prefix = make(Prefix, 32+len(actualRootPrefix))
copy(prefix, actualRootPrefix)
prefix = prefix[:len(actualRootPrefix)]
}
// Visit the root first. Not that this works for empty trie as well since
// in that case item == nil && len(children) == 0.
if trie.item != nil {
if err := visitor(prefix, trie.item); err != nil {
if err == SkipSubtree {
return nil
}
return err
}
}
// Then continue to the children.
return trie.children.walk(&prefix, visitor)
}
func (trie *Trie) longestCommonPrefixLength(prefix Prefix) (i int) {
for ; i < len(prefix) && i < len(trie.prefix) && prefix[i] == trie.prefix[i]; i++ {
}
return
}
func (trie *Trie) dump() string {
writer := &bytes.Buffer{}
trie.print(writer, 0)
return writer.String()
}
func (trie *Trie) print(writer io.Writer, indent int) {
fmt.Fprintf(writer, "%s%s %v\n", strings.Repeat(" ", indent), string(trie.prefix), trie.item)
trie.children.print(writer, indent+2)
}
// Errors ----------------------------------------------------------------------
var (
SkipSubtree = errors.New("Skip this subtree")
ErrNilPrefix = errors.New("Nil prefix passed into a method call")
)